image-match/python/py/Lib/site-packages/parso/utils.py

import re
import sys
from ast import literal_eval
from functools import total_ordering
from typing import NamedTuple, Union

# The following is a list in Python that are line breaks in str.splitlines, but
# not in Python. In Python only \r (Carriage Return, 0xD) and \n (Line Feed,
# 0xA) are allowed to split lines.
_NON_LINE_BREAKS = (
    '\v',  # Vertical Tabulation 0xB
    '\f',  # Form Feed 0xC
    '\x1C',  # File Separator
    '\x1D',  # Group Separator
    '\x1E',  # Record Separator
    '\x85',  # Next Line (NEL - Equivalent to CR+LF.
             # Used to mark end-of-line on some IBM mainframes.)
    '\u2028',  # Line Separator
    '\u2029',  # Paragraph Separator
)


class Version(NamedTuple):
    major: int
    minor: int
    micro: int


def split_lines(string: str, keepends: bool = False) -> "list[str]":
    r"""
    Intended for Python code. In contrast to Python's :py:meth:`str.splitlines`,
    looks at form feeds and other special characters as normal text. Just
    splits ``\n`` and ``\r\n``.
    Also different: Returns ``[""]`` for an empty string input.

    In Python 2.7 form feeds are used as normal characters when using
    str.splitlines. However in Python 3 somewhere there was a decision to split
    also on form feeds.
    """
    if keepends:
        lst = string.splitlines(True)

        # We have to merge lines that were broken by form feed characters.
        merge = []
        for i, line in enumerate(lst):
            try:
                last_chr = line[-1]
            except IndexError:
                pass
            else:
                if last_chr in _NON_LINE_BREAKS:
                    merge.append(i)

        for index in reversed(merge):
            try:
                lst[index] = lst[index] + lst[index + 1]
                del lst[index + 1]
            except IndexError:
                # index + 1 can be empty and therefore there's no need to
                # merge.
                pass

        # The stdlib's implementation of the end is inconsistent when calling
        # it with/without keepends. One time there's an empty string in the
        # end, one time there's none.
        if string.endswith('\n') or string.endswith('\r') or string == '':
            lst.append('')
        return lst
    else:
        return re.split(r'\n|\r\n|\r', string)


def python_bytes_to_unicode(
    source: Union[str, bytes], encoding: str = 'utf-8', errors: str = 'strict'
) -> str:
    """
    Checks for unicode BOMs and PEP 263 encoding declarations. Then returns a
    unicode object like in :py:meth:`bytes.decode`.

    :param encoding: See :py:meth:`bytes.decode` documentation.
    :param errors: See :py:meth:`bytes.decode` documentation. ``errors`` can be
        ``'strict'``, ``'replace'`` or ``'ignore'``.
    """
    def detect_encoding():
        """
        For the implementation of encoding definitions in Python, look at:
        - http://www.python.org/dev/peps/pep-0263/
        - http://docs.python.org/2/reference/lexical_analysis.html#encoding-declarations
        """
        byte_mark = literal_eval(r"b'\xef\xbb\xbf'")
        if source.startswith(byte_mark):
            # UTF-8 byte-order mark
            return 'utf-8'

        first_two_lines = re.match(br'(?:[^\r\n]*(?:\r\n|\r|\n)){0,2}', source).group(0)
        possible_encoding = re.search(br"coding[=:]\s*([-\w.]+)",
                                      first_two_lines)
        if possible_encoding:
            e = possible_encoding.group(1)
            if not isinstance(e, str):
                e = str(e, 'ascii', 'replace')
            return e
        else:
            # the default if nothing else has been set -> PEP 263
            return encoding

    if isinstance(source, str):
        # only cast str/bytes
        return source

    encoding = detect_encoding()
    try:
        # Cast to unicode
        return str(source, encoding, errors)
    except LookupError:
        if errors == 'replace':
            # This is a weird case that can happen if the given encoding is not
            # a valid encoding. This usually shouldn't happen with provided
            # encodings, but can happen if somebody uses encoding declarations
            # like `# coding: foo-8`.
            return str(source, 'utf-8', errors)
        raise


def version_info() -> Version:
    """
    Returns a namedtuple of parso's version, similar to Python's
    ``sys.version_info``.
    """
    from parso import __version__
    tupl = re.findall(r'[a-z]+|\d+', __version__)
    return Version(*[x if i == 3 else int(x) for i, x in enumerate(tupl)])


class _PythonVersionInfo(NamedTuple):
    major: int
    minor: int


@total_ordering
class PythonVersionInfo(_PythonVersionInfo):
    def __gt__(self, other):
        if isinstance(other, tuple):
            if len(other) != 2:
                raise ValueError("Can only compare to tuples of length 2.")
            return (self.major, self.minor) > other
        super().__gt__(other)

        return (self.major, self.minor)

    def __eq__(self, other):
        if isinstance(other, tuple):
            if len(other) != 2:
                raise ValueError("Can only compare to tuples of length 2.")
            return (self.major, self.minor) == other
        super().__eq__(other)

    def __ne__(self, other):
        return not self.__eq__(other)


def _parse_version(version) -> PythonVersionInfo:
    match = re.match(r'(\d+)(?:\.(\d{1,2})(?:\.\d+)?)?((a|b|rc)\d)?$', version)
    if match is None:
        raise ValueError('The given version is not in the right format. '
                         'Use something like "3.8" or "3".')

    major = int(match.group(1))
    minor = match.group(2)
    if minor is None:
        # Use the latest Python in case it's not exactly defined, because the
        # grammars are typically backwards compatible?
        if major == 2:
            minor = "7"
        elif major == 3:
            minor = "6"
        else:
            raise NotImplementedError("Sorry, no support yet for those fancy new/old versions.")
    minor = int(minor)
    return PythonVersionInfo(major, minor)


def parse_version_string(version: str = None) -> PythonVersionInfo:
    """
    Checks for a valid version number (e.g. `3.8` or `3.10.1` or `3`) and
    returns a corresponding version info that is always two characters long in
    decimal.
    """
    if version is None:
        version = '%s.%s' % sys.version_info[:2]
    if not isinstance(version, str):
        raise TypeError('version must be a string like "3.8"')

    return _parse_version(version)